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Year 10 Interactive Maths - Second Edition


Problem Solving Unit

Problem 4.1  The Numbers

Consider the triangle given in the diagram. D, E and F are three unknown numbers. The numbers stated near the sides of the triangle indicate the sum of the numbers on the neighbouring vertices. Thus:

D + E = 15, E + F = 13, F + D = 14

What are D, E and F?

Triangle DEF has side DE labelled 15, side EF labelled 13 and side DE labelled 14.
Now solve the following similar problem.

Triangle ABC has side AB labelled 14, side BC labelled 3 and side AB labelled 6.

 

Problem 4.2  Finite Difference Table

Consider a finite difference table of the linear function y = 2x + 5.

The finite difference table indicates a finite difference of 2 for the (x, y) pairs (0,5), (1,7), (2,9), (3,11), (4,13).

For the linear function y = 2x + 5, the first difference in a finite difference table is constant and it is equal to 2. This constant is the gradient of the linear function. When x = 0, y = 5. We can write this as y(0) = 5 which is the y-intercept.

Consider the finite difference table of the general linear function  y = mx + c where m is the gradient and c is the y-intercept.

The finite difference table indicates a finite difference of m for the (x, y) pairs (0,c), (1,m+c), (2,2m+c), (3,3m+c), (4,4m+c).

Clearly, the first difference is the constant m; and it is the gradient of the linear function.
y-intercept = y(0) = c.

From this we can infer that:

If a finite difference table for a function generates a constant first difference, then it must be a linear function. Note that if the table also includes x = 0, it allows us to easily find a rule for the linear function.


Example 10

Find a rule for the function specified by the following table of values:

(x,y) pairs of (0,4), (1,7), (2,10), (3,13)

Solution:

The finite difference table indicates a finite difference of 3 for the (x, y) pairs (0,4), (1,7), (2,10), (3,13).

The first difference is constant.  Therefore, the table of values represents a linear function of the
form y = mx + c.

To find m and c, we compare this table with the finite difference table of y = mx + c.

Therefore m = 3, c = 4.

So, the rule for the linear function is y = 3x + 4.

Note:

A table of values must include x = 0 as it helps to find the value of c


Using a TI-83 Graphics Calculator

Clear any list(s) within the STAT menu (and if there are graphs in memory clear them using the
Y = menu). Select EDIT from the STAT menu and enter x values under L1 and y values under
L2. Both lists should have the same number of entries.

Select Plot 1 on from the STAT PLOT menu and turn the other plots off. Highlight the second
plot that gives a line graph. Choose L1 for the Xlist and L2 for the Ylist (if they are not already
highlighted).

Choose Zoom Stat from the ZOOM menu to obtain the graph of the data, which is a straight
line. Then choose LinReg in the CALC section of the STAT menu. The screen display shows
that the relation

y = 3x + 4

fits the data.


Example 11

Find a rule for the function specified by the following table of values:

(x,y) ordered pairs of (3,3), (4,5), (5,7)

Solution:

The finite difference table indicates a finite difference of 2 for the (x, y) pairs (3,3), (4,5), (5,7).

The first difference is constant.  Therefore, the table of values represents a linear function of gradient 2.  So, m = 2.  To find c = y(0) we extend the table as shown below.

The finite difference table indicates a finite difference of 2 for the (x, y) pairs (0,-3), (1,-1), (2,1), (3,3), (4,5), (5,7).

Therefore m = 2, c = y(0) = -3.

The linear function is y = mx + c, so y = 2x - 3


Using a TI-83 Graphics Calculator

Clear any lists within the STAT menu (and if there are graphs in memory, clear them using the
Y = menu). Select EDIT from the STAT menu and enter x values under L1 and y values under
L2. Both lists should have the same number of entries.

Select Plot 1 on from the STAT PLOT menu and turn the other plots off. Highlight the second
plot that gives a line graph. Choose L1 for the Xlist and L2 for the Ylist (if they are not already
highlighted).

Choose Zoom Stat from the ZOOM menu to obtain the graph of the data which is a straight line.
Then choose LinReg in the CALC section of the STAT menu. The screen display shows that the
relation

y = 2x - 3

fits the data.


Just to recap:

For any linear function, the first difference in a finite difference table is always constant. This constant is the gradient of the linear function and the y-intercept is given by y(0).


Find a rule for the function specified by the following tables; and check your answers with a graphics calculator.

a. (x,y) ordered pairs of (0,1), (1,2), (2,3), (3,4) b. (x,y) ordered pairs of (0,2), (1,3), (2,4), (3,5)

c.

(x,y) ordered pairs of (0,3), (1,4), (2,5), (3,6)

d.

(x,y) ordered pairs of (0,-1), (1,0), (2,1), (3,2)

e.

(x,y) ordered pairs of (0,4), (1,6), (2,8), (3,10)

f.

(x,y) ordered pairs of (0,3), (1,5), (2,7), (3,9)

g.

(x,y) ordered pairs of (0,1), (1,4), (2,7), (3,10)

h.

(x,y) ordered pairs of (0,5), (1,8), (2,11), (3,14)

i.

(x,y) ordered pairs of (0,5), (1,7), (2,9), (3,11)

j.

(x,y) ordered pairs of (0,7), (1,9), (2,11), (3,13)

k.

(x,y) ordered pairs of (0,8), (1,12), (2,16), (3,20)

l.

(x,y) ordered pairs of (0,7), (1,12), (2,17), (3,22)

m.

(x,y) ordered pairs of (2,5), (3,8), (4,11), (5,14)

n.

(x,y) ordered pairs of (2,1), (3,3), (4,5), (5,7)

o.

(x,y) ordered pairs of (2,-3), (3,-1), (4,1), (5,3)


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