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Year 7 Interactive Maths - Second Edition


Equations Involving Multiplication

Consider the equation
16 - 4 = 12

Clearly both the left-hand side and right-hand side equal 12.  That is LHS = RHS


If we halve the weight on both sides, then we obtain:
(16-4)/2 = 12/2

The left-hand side and the right-hand side both equal 6.  Therefore, LHS = RHS

We notice that the statement
16 - 4 = 12
remains a true statement when both sides of the equation are divided by 2.

This suggests that equations behave like balances.  If the same number divides the mass in both scales of a balance, it still remains balanced.  This implies that we can divide both sides of an equation by the same number to get a new equation.


Consider the equation 2x = 14.

If you put 2x kg in one of a pair of scales and add 14 kg to the other, the scales will show that 2x kg is equal to 14 kg.  That is 2x = 14

Halving the weight in each scale of the balance will result in x kg on one scale and 7 kg on the other.  The scales will show that x kg = 7 kg.  That is x = 7

After halving the weight in both scales, the scales remain balanced.


From the preceding discussion, we can state that:

To solve an equation, we can divide both sides of an equation by the same number.


Example 5

Solve the equation 7x = 56 for x.

Solution:

Divide both sides by 7 to find x = 8


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